Question

find the product of largest 5 gigit and the 3 digit number using distributive law​

Answer 1

Answer:

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Step-by-step explanation:

99899001 is the product of largest 5 digit no. and largest 3 digit no using distributive property.

Given:

Largest 5 -digit number and largest 3- digit number  

To find:

Product of largest 5 -digit number and largest 3- digit number using distributive property = ?

Solution:

The largest five digit number in the number system is = 99999

Similarly, the largest three digit number in the system is = 999

Using Distributive properties which is, a \times (b - c) = (a \times b) - (a \times c)a×(b−c)=(a×b)−(a×c)

Therefore, multiplying the largest 5 digit number with largest 3 digit number we get

99999 \times 999 = 99999 \times (1000-1)99999×999=99999×(1000−1)

Similarly applying distributive properties to the RHS we get

=( 99999 \times 1000)- (99999 \times 1)=(99999×1000)−(99999×1)

= 99999000-99999=99999000−99999

Therefore, the number formed after multiplication of 5 large digit and 3 large digit is  

99999 \times 999 = 99899001.99999×999=99899001.

99899001 is the product of largest 5-digit no. and largest 3 -digit no using distributive property.