find the product of (m-1) (m+2) (m-3)
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Answer:
(m-1) (m+2)
=( m² +2m -m-2) (m-3)
=m³-3m²
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Given:- (m -1), (m -2), (m -3)
[(m×m) + (m × -2) + (-1 × m) + (-1 × -2)] (m -3)
= (m² -2m -m +2) (m -3)
= (m² -3m + 2) (m -3)
= (m² × m) + (m² × -3) + (-3m × m) + (-3m × -3) + (2 × m) + (2 × - 3)
= m³ -3m² -3m² +9m +2m -6
= m³ -6m² +11m -6
Hence, (m -1) (m -2) (m -3) = m³ -6m²+ 11m -6
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