Question

Find the product of: (p2 + 2pq + q2 ) × 3p

Answer 1

Given:

$(p^2+2pq+q^2)*3p$

To find product:

we  will multiply the values

$(3p*2p^2)+3p*2pq+3p*q^2$

We get the answer as:

$3p^3+6p^2q+3pq^2$

Answer 2

Hint:

Let us know Distributive Property of Algebra before we solve the problem

$\quad a\times (b+c)=a\times b+a\times c$

Step-by-step explanation:

Now, $(p^{2}+2pq+q^{2})\times 3p$

• Use Distributive Property which is mentioned above.

$=p^{2}\times 3p+2pq\times 3p+q^{2}\times 3p$

$=3\times p^{2}\times p+2\times 3\times p\times p\times q+3\times p\times q^{2}$

$=3p^{2+1}+6p^{1+1}q+3pq^{2}$

• Since $a^{m}\times a^{n}=a^{m+n}$

$=3p^{3}+6p^{2}q+3pq^{2}$

Final answer:

$(p^{2}+2pq+q^{2})\times 3p=3p^{3}+6p^{2}q+3pq^{2}$

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