Question

find the product of root 3 and cube root 2​

Answer 1

1.732050808 for root 3

hope it's helpful

Answer 2

$\sqrt{3} \times \sqrt[3]{2} = \sqrt[6]{108}$

Solution:

Given that,

We have to find the product of root 3 and cube root 2​

$\sqrt{3} \times \sqrt[3]{2}$

Rewrite

$3^{\frac{1}{2}} \times 2^{\frac{1}{3}}\\\\\text{Make the powers same }\\\\3^{\frac{1}{2} \times \frac{3}{3}} \times 2^{\frac{1}{3} \times \frac{2}{2}}\\\\3^{\frac{3}{6}} \times 2^{\frac{2}{6}}\\\\(3^3)^{\frac{1}{6}} \times (2^2)^{\frac{1}{6}}\\\\(27 \times 4)^{\frac{1}{6}}\\\\108^{\frac{1}{6}}\\\\ \sqrt[6]{108}$

Thus product is found

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