Question

Find the product of roots of the quadratic equation 6x^2+x-2=0.​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

x =-b+_(b^2-4ac)^1/2 divided by 2a

Where,

a=6

b=-1

c=-2

Substituting the values in the equation,

x=-(-1)×_(-1^2+4×6×2)^1/2 divided by 2×6

=1+_(49)^1/2 divided by 12

x=1+7/12 = 8/12= 2/3. or

x=1-7/12=-6/12=-1/2

Therefore the values of x are

x=2/3

Or

x=-1/2