Question

Find the product of sum of three consecutive smallest positive numbers with  the sum of their corresponding opposites.

​

Answer 1

Answer:

Step-by-step explanation:

Let us assume the numbers to be a, b, c

Therefore their opposites are -a, -b, -c

Now product of the sum of the two means :

[a+b+c]×[-a+(-b)+(-c)]

=> [a + b + c][-a -b -c]

=> -a^2 -b^2 -c^2 - 2ab - 2bc - 2ac

=> - (a + b + c) ^2

Now for smallest values :

a= 1, b =2 and c =3

-(1+2+3)^2 => -(6)^2 => -36

I hope it helps you :D

Please mark as the brainliest answer. Its just a click for you but a world for me