find the product of sum of three consecutive smallest positive numbers with the sum of their corresponding opposites
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Answer:
Let us assume the numbers to be a, b, c
Therefore their opposites are -a, -b, -c
Now product of the sum of the two means :
[a+b+c]×[-a+(-b)+(-c)]
=> [a + b + c][-a -b -c]
=> -a^2 -b^2 -c^2 - 2ab - 2bc - 2ac
=> - (a + b + c) ^2
Now for smallest values :
a= 1, b =2 and c =3
-(1+2+3)^2 => -(6)^2 => -36
Hope it helps you~
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