Question

find the product of terms
(y2-4)(2y2+3y)​

Answer 1

$( {y}^{2} - 4)(2 {y}^{2} - 3y)$

$= {y}^{2} (2 {y}^{2} - 3y) - 4((2 {y}^{2} - 3y)$

$= 2 {y}^{4} - 3 {y}^{3} - 8 {y}^{2} - 12y$

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Answer 2

Answer:

(y

2

−4)(2y

2

−3y)

= {y}^{2} (2 {y}^{2} - 3y) - 4((2 {y}^{2} - 3y)=y

2

(2y

2

−3y)−4((2y

2

−3y)

= 2 {y}^{4} - 3 {y}^{3} - 8 {y}^{2} - 12y=2y

4

−3y

3

−8y

2

−12y

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