Find the product of the cube of -2/3 and the square of 5/-7
Answers
Answer:
The value of the cube root of 5 rounded to 6 decimal places is 1.709976. It is the real solution of the equation x3 = 5. The cube root of 5 is expressed as ∛5 in the radical form and as (5)⅓ or (5)0.33 in the exponent form. The prime factorization of 5 is 5, hence, the cube root of 5 in its lowest radical form is expressed as ∛5.
Cube root of 5: 1.709975947
Cube root of 5 in Exponential Form: (5)⅓
Cube root of 5 in Radical Form: ∛5
The cube root of 5 is the number which when multiplied by itself three times gives the product as 5. The number 5 is prime. Therefore, the cube root of 5 = ∛5 = 1.71.
Its formula is ∛a ≈ x ((x3 + 2a)/(2x3 + a))
where,
a = number whose cube root is being calculated
x = integer guess of its cube root.
Here a = 5
Let us assume x as 1
[∵ 13 = 1 and 1 is the nearest perfect cube that is less than 5]
⇒ x = 1
Therefore,
∛5 = 1 (13 + 2 × 5)/(2 × 13 + 5)) = 1.57
⇒ ∛5 ≈ 1.57
Therefore, the cube root of 5 is 1.57 approximately.
Answer:
product of the cube of -2/3 is -216
Step-by-step explanation:
1)-2³×3³= -8×27
= -216