Question

find the product of the following 4x ,-3,-2xy and 7y square​

Answer 1

Answer:

The product of the following $4x ,-3,-2xy$ and $7y^2$ is $168x^2y^3$

Step-by-step explanation:

When we multiply a monomial by a monomial then the coefficients of the monomials are multiplied together and then the variables are multiplied.

The product of the following $4x ,-3,-2xy$ and $7y^2$ is

$4x \times (-3) \times (-2xy) \times (7y^2)\\= 4 \times (-3) \times (-2) \times 7 \times x \times (xy) \times y^2\\= -12 \times (-2) \times 7 \times x^2y \times y^2\\ = 24 \times 7 \times x^2y^3\\= 168x^2y^3$

Answer 2

Answer:

168 x^2 y^3

Step-by-step explanation:

(4x) x (-3) x (-2xy) x (7y^2)

=168 x^2 y^3

Hope it helps :)