Math, asked by sharmashweta350, 4 months ago

find the product of the following 8lm²n, 4l²mn²​

Answers

Answered by rohitpanghal801
1

Answer:

the product of the following 8lm²n, 4l²mn²

81m^2n*41^2mn^2

=136,161m^3n°3

Answered by Anonymous
1

\huge\underline\mathtt\color{red}{Answer}

 = 8l {m}^{2} n \times 4 {l}^{2}

 = 32 {l}^{3}  {m}^{2} n

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