Question

Find the product of the following binomials :

(i) (7x – 6y) (7x – 6y) (ii) (3a + b) (b – 3a) (iii)(2x + 10) (2x – 5)


3. Find the value of using identities :

(i) 47 x 53 (ii) (35.4)2 – (14.6)2



4. If cost of 5 pencils is same as the cost of notebook. If the cost of 7 pencils and 7 notebooks

together is 210, then find the cost of 2 pencils and 3 notebooks



plz answer to these.questions will mark as brainalist​

Answer 1

Answer:

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Step-by-step explanation:

$Product= (7x-6y)(7x-6y) \\ \\\implies({7x-6y})^{2} \\ \\⟹(7x−6y) {}^{2} =({7x})^{2}-2\times 7x\times6y+({6y})^{2} \\\\ ⟹(7x) {}^{2} −2×7x×6y+(6y) {}^{2} \\ \\\implies{49x}^{2}-84xy+{36y}^{2} \\\\⟹49x {}^{2}−84xy+36y {}^{2}$

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$According \: \: to \: \: the \: \: algebraic \: \: identity : \\ a^2-b^2=(a+b)(a-b) \\\\The \: \: given \: \: expression : \\ (35.4)^2 - (14.6)^2 \\\\ Here \: \: a= 35.4 \: \: and \: \: b = 14.6 \\\\ Then, (35.4)^2 - (14.6)^2 = (35.4+14.6)(35.4-14.6) \\ [∵ a^2-b^2=(a+b)(a-b)]\\\\ =(50.00)(20.80)\\\\ =1040.00 \\\\ ∴ The \: \:value \: \: of \: \: (35.4)^2 - (14.6)^2=1040$

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For Q4, see images