Math, asked by rajeshkumar61, 10 months ago

find the product of the following . i) (-3)× 2×(-5). ii) 5×(-7)×8. iii). 3×(-8)×(-4). iv). (-20)×12×(-10). v) (-9)×(-35)×0. vi). (-3)×(-5)×(-7). vii). (-3)×(-6)×(-9)×(-12). viii) (-2)×(-4)×(-6)×(-8). ​

Answers

Answered by Anonymous
10

Solution :

(i) (-3)× 2×(-5)

= (-3)(-5) * 2

= 15 *2

=30

(ii) 5 (-7)*8

=40*-7

=-280

(iii) 3×(-8)×(-4)

= 3*32

= 64

(iv) (-20)×12×(-10).

= 200 * 12

= 2400

(v) (-9)×(-35)×0.

= -9 * 0

= 0

(vi) (-3)×(-5)×(-7)

= 15 * -7

= -105

(vii) (-3)×(-6)×(-9)×(-12)

= 18 * 108

= 1944

(viii) (-2)×(-4)×(-6)×(-8).

= 8 * 48

= 384

Similar questions
Math, 5 months ago