Question

Find the product of the following monomials
(i) xy, x²y, xy, x
(ii) a, b, ab, a³b, ab²
(iii) kl, lm, km, klm
(iv) pq ,pqr, r
(v) −3a, 4ab, −6c, d

Answer 1

Answer:

(i) x^5 y^3

(ii)a^7 b^5

(iii)k^3 l^3 m^3

(iv)p^2 q^2 r^2

(v)-12a^2 b -6c d

Answer 2

x^5y^3  ; a^6b^5  ; k^3l^3m^3  ; p²q²r²  ; 72a²bcd

Step-by-step explanation:

As per the law of exponentiation, in order to multiply two numbers having the same base and different power, we just need to add the powers to get the product.

So applying the above rule, we get the products of the monomials.

(i) xy * x²y * xy * x = x^ (1+2+1+1) y^ (1+1+1) = x^5y^3

(ii) a * b * ab * a³b *  ab² = a^(1+1+3+1)b^(1+1+1+2) = a^6b^5

(iii) kl, lm, km, klm = k^(1+0+1+1)l^(1+1+0+1)m^(0+1+1+1) = k^3l^3m^3

(iv) pq ,pqr, r = p^(1+1)q^(1+1)r^(1+1) = p²q²r²

(v) −3a, 4ab, −6c, d = (-3*4*-6*1) a^(1+1)bcd = 72a²bcd

Please refer to the attached pictures for the correct format