Question

Find the product of the following pairs:
(i) 6, 7k
(ii) −3l,−2m
(iii) −5t² −3t²
(iv) 6n, 3m
(v) −5p², −2p

Answer 1

ʜʏ ғʀɪᴇɴᴅ ʜᴇʀᴇ ɪs ʏᴏᴜʀ ᴀɴsᴡᴇʀ

1. 42k

2. 62m

3. 15t^4

4. 18nm

5. 10p^2

Hope it help you☺️

Answer 2

product of the following pairs:

(i) 6, 7k  =42K

(ii) −3l,−2m  = 6nm

(iii) −5t², −3t² =$15\textrm{t}^{4}$

(iv) 6n, 3m =18nm

(v) −5p², −2p=$10\textrm{p}^{3}$

Step-by-step explanation:

Product of the following algebraic expression pairs are

(i) $6\times7\textrm{k}=42\textrm{k}$

(ii) $\textrm{(-3l)}\times\textrm{(-2m)}=6\textrm{lm}$

(iii) $(-5\textrm{t}^{2}) \times (-3\textrm{t}^{2} )=15\textrm{t}^{2+2} =15\textrm{t}^{4}$

(iv) $6\textrm{n}\times3\textrm{m}=18\textrm{nm}$

(v) $(-5\textrm{p}^{2} )\times(-2\textrm{p})=10\textrm{p}^{3}$