find the product of the following using the identity (x + a) (x + b) = x² + (a + b) x + ab.
i) (x + 4) (x + 7)
ii) (x + 6) ( x + 9)
iii) (x + 9) (x - 10)
iv) (x - 9) (x - 10)
v) ( x - 12) (x + 13)
vi) (x + 7) (x + 13)
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Answer:
Formula
(x+a) (x+b) = x² + (a+b)x + ab
i) x = x
a = 4
b = 7
x² + (4+7)x + 4×7
x² + 11x + 28
ii) x = x
a = 6
b = 9
x² + (6+9)x + 6×9
x² + 15x + 54
iii) x = x
a = 9
b = -10
x² + (9-10)x + 9×-10
x² - 1x - 90
iv) x = x
a = -9
b = -10
x² + (-9-10)x + -9×-10
x² - 19x + 90
v) x = x
a = -12
b = 13
x² + (-12+13)x + -12×13
x² + (1)x + -156
vi) x = x
a = 7
b = 13
x² + (7+13)x + 7×13
x² + 20x + 91
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