Question

Find the product of the given polynomial p x) = 3x³ + 2x-x²+8 and q(x)=7x+2​

Answer 1

(7x + 2) (3x3 + 2x – x2 + 8) = 7x(3x3 + 2x – x2 + 8) + 2x(3x3 + 2x – x2 + 8) =

21x4 + 14x2 – 7x3 + 56x + 6x3 + 4x – 2x2 + 16 =

21x4 – x3 + 12x4 + 60x + 16

Answer 2

Answer:

21x^4-x³+ 12x²+60x+ 16

Step-by-step explanation:

=(3x³ + 2x-x²+8)(7x+2​)

=7x * (3x³ + 2x-x²+8)+ 2 * (3x³ + 2x-x²+8)

=(7x*3x³)+ (7x*2x) - (7x * x²) + (7x* 8) +   (2* 3x³) + (2* 2x) - (2* x²)+ (2*8)

= 21x^4 + 14x² - 7x³ + 56x  + 6x³ + 4x - 2x² + 16

now combining all the like terms

=21x^4 +14x²- 2x²+ 6x³- 7x³+56x+ 4x+ 16

= 21x^4+ 12x²-x³+ 60x+ 16

now arranging terms

=21x^4-x³+ 12x²+60x+ 16