Question

Find the product of the greatest 4-digitnumber and the greatest 3-digit numberusing the properties of whole numbers.​

Answer 1

Answer:

Thnk u

Step-by-step explanation:

Greatest number of four digits = 9999,

Greatest number of three digits = 999,

Required product =9999×999,

=9999×(1000–1)

=9999×1000–9999×1 (using distributivity)

=(10000–1)×1000–(10000–1)×1

=10000000–1000–10000+1

=10000001–11000

=9989001.

Answer 2

Answer:

999x9999 = 9989001

Step-by-step explanation:

The greatest 4 digit number is 9999.

The greatest 3 digit number is 999.

The product of the greatest 4 digit number and the greatest 3 digit number

i.e.  

We can split, 999=1000-1

So,  

Applying distributive property of whole number,

Multiplication of a whole number is distributed over the difference of the whole numbers i.e.

a(b-c) = ab-ac

9999 x ( 1000 - 1 ) = 9999x 1000 - 9999 - 1

9999 x ( 1000 - 1 ) = 9999000  - 9999

9999 x ( 1000 - 1 ) = 9989001

Therefore, The required product is 9999 x 999 = 99809001

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