Math, asked by msgarimarai, 11 months ago

find the product of the greatest number of 3-digits and the greatest number of 2-digits formed by 3 and 6.​

Answers

Answered by hermione2007
17

Step-by-step explanation:

greatest 3 digit number formed with 3 and 6 = 663

greatest 2 digit number formed with 3 and 6 =

63

63×663=41769

This should be the answer if your question is correct.

Hope this helps.

Please mark as brainliest!

Answered by syed2020ashaels
2

The given question that we have to find the product of the greatest number of 3-digits and the greatest number of 2-digits formed by 3 and 6.

The greatest 3 digit number formed by 3 and 6 is

the 3 digit number formed by 3 and 6 is 363,336,

363,336,663,633,366,333,666,636

The greatest 3 digit number is 666

The 2 digit number formed by 3 and 6 is

36,63,33,66

The greatest 2 digit number is 66.

The product of greatest 3 digit and greatest 2 digit number is

666 \times 66 = 43956

Therefore, the final answer is the product of greatest 3 digit and greatest 2 digit number formed by 3 and 6 is 43956.

# spj2

we can find the similar questions through the link

https://brainly.in/question/19182848?referrer=searchResults

Similar questions