Math, asked by dimnwobi692, 7 months ago

Find the product of the HCF of 4x , 12x^2y and then LCM of 5xy^2 and 3

Answers

Answered by bhavaniprasad33
1

Step-by-step explanation:

HCF is 4x

LCM is 15xy

their product is 60x²y

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Answered by topwriters
0

60x²y²

Step-by-step explanation:

Given: 4x , 12x^2y and  5xy^2 and 3.

Find: The product of the HCF of 4x , 12x^2y and then LCM of 5xy^2 and 3.

Solution:

4x = 2 * 2 * x

12x²y = 2 * 2 * 3 *  x * x * y

HCF = 2 * 2 * x = 4x

5xy² = 5 * x * y * y

3 = 3

LCM = 3 * 5 * x * y * y = 15xy²

HCF * LCM = 4x * 15xy² = 60x²y²

Product of the HCF of 4x , 12x^2y and then LCM of 5xy^2 and 3 = 60x²y²

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