Find the product of the HCF of 4x , 12x^2y and then LCM of 5xy^2 and 3
Answers
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Step-by-step explanation:
HCF is 4x
LCM is 15xy
their product is 60x²y
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60x²y²
Step-by-step explanation:
Given: 4x , 12x^2y and 5xy^2 and 3.
Find: The product of the HCF of 4x , 12x^2y and then LCM of 5xy^2 and 3.
Solution:
4x = 2 * 2 * x
12x²y = 2 * 2 * 3 * x * x * y
HCF = 2 * 2 * x = 4x
5xy² = 5 * x * y * y
3 = 3
LCM = 3 * 5 * x * y * y = 15xy²
HCF * LCM = 4x * 15xy² = 60x²y²
Product of the HCF of 4x , 12x^2y and then LCM of 5xy^2 and 3 = 60x²y²
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