Find the product of the Lcmand hcf of9,12 and 18
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9,12,18 3* 3,4,6 =2* 3,2,3 =36 *3 =108 (previous)=LCM and HCF = 12/9 remainder =3 18 is also divisible by 3 so HCF =3 so ANSWER IS LCM=108 and HCF =3 THANKS
JAMES1111:
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