find the product of the roots of 1/√6 - 3 x - 1/√2 =0 ( need it urgently)
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1
Answer:
Given:
3x
2
−
2
6
x+
2=
0
3x
2
−
6
x−
6
x+
2=
0,
3
x(
3
x−
2
)−
2
(
3
x−
2
)=
0
(
3
x−
2
)(
3
x−
2
)=
0∴
3
x−
2
=
0
or
3
x−
2
=
0
∴
3
x=
2
or
3
x=
2
,x=
3
2
or
x=
3
2
So, the root is repeated twice, one for each repeated factor
(
3
x−
2
)l.
∴
The two equal roots of
3x
2
−
2
6
x+
2=
0
are
3
2
,
3
2
.
Step-by-step explanation:
i hope this helps you
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