Math, asked by achanchal456, 10 months ago

Find the product of the sum of digits of
the smallest 4-digit number divisible by 6
and the sum of digits of the smallest
5-digit number divisible by 11.
(A) 4
(C) 6
(D) 7
(B) 5​

Answers

Answered by viranchya
2

Answer:

(C) 6

Step-by-step explanation:

smallest 4 digit no. = 1000

smallest 4 digit no. divisible by 2 and 3 i.e. 6 = 1002

1+0+0+2=3

smallest five digit no. = 10000

smallest five digit no. divisible by 11 = 10010

1+0+0+1+0=2

2*3=6

hence answer is (C) 6

Similar questions