Question

Find the product of the zeores of 2x^+kx+6

Answer 1

$\huge \boxed{ \underline{ \underline{ \bf{Answer}}}}$

Correct Question: Find the product of the zeros of 2x² + kx +  6.

Solution :-

⇒ A polynomial of degree 1 is called a Linear polynomial.

⇒ A polynomial of degree 2 is called a Quadratic polynomial.

⇒ A  polynomial of degree 3 is called a Cubic polynomial.

→ α and β are Greek letters pronounced as 'alpha' and ' beta' respectively.

→ α and β are the zeroes of the quadratic polynomial ax² + bx + c.

$\implies \boxed{\mathsf{2x^{2}\:+\:kx\:+\:6}}$

• Sum of the zeroes = α + β

• Product of the zeroes = αβ

→ α + β = -b/a

→ αβ = c/a

a = 2 , b = k and c = 6 .

Sum of the zeroes = -b/a

⇒ -k/2

Product of the zeroes = c/a

⇒ 6/2

⇒ 3

∴ αβ = 3 . ( Product of the zeroes ! )

Answer 2

Answer:   = 3

Step-by-step explanation:

Given,

p(x): 2x² + kx + 6

Comparing the following equation with standard form of equation of 2nd degree ax² + bx +c

a = 2

b = k

c = 6

We know that,

Product of zeroes  = c/a

                               = 6/3

                               = 3

Note:- Its only true for quadratic equations.

Sum of zeroes   = -b/a

Product of zeroes = c/a