Question

find the product of the zeroes of -2x2+kx+6

Answer 1

p(x) = -2x² + kx + 6 = 0

a = -2

b = k

c = 6

Product of zeroes = c/a

Product of zeroes = 6/-2

Product of zeroes = -3.

So -3 is the answer.

Thank you...

Answer 2

The product of the zeroes of quadratic equation is -3.

Step-by-step explanation:

Given : Quadratic equation $-2x^2+kx+6$

To find : The product of the zeroes of quadratic equation ?

Solution :

Quadratic equation $-2x^2+kx+6$

Let $\alpha$ and $\beta$ are zeros of quadratic equation.

The product of zeros is $\alpha \beta=\frac{c}{a}$

Here, a=-2, b=k and c=6

Substitute in the formula,

$\alpha \beta=\frac{6}{-2}$

$\alpha \beta=-3$

Therefore, the product of the zeroes of quadratic equation is -3.

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