Question

Find the product of the zeroes of p(x)=63x2-7x-9​

Answer 1

$Given \: Quadratic \: polynomial : \\p(x) = 63x^{2} - 7x - 9$

/* compare this with ax² + bx + c , we get */

$a = 63 , \: b = -7 \: and \: c = -9$

$\blue {i ) Sum \: of \:the \: zeroes} \\= \frac{-b}{a} \\=\frac{-(-7)}{63} \\= \frac{7}{63} \\= \frac{1}{9} \: --(1)$

$\orange {ii ) Product \: of \:the \: zeroes} \\= \frac{c}{a} \\=\frac{-9}{63} \\= \frac{-1}{7} \: --(2)$

Therefore.,

$\red { Product \: of \:the \: zeroes}\green {=\frac{-1}{7}}$

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Answer 2

Answer:

Product of zeroes = -1/7

Step-by-step explanation:

63x^2-7x-9=0

a=63, b=-7, c=-9

Product of zeroes = c/a

= -9/63

= -1/7.

HOPE THIS BRING A SMILE IN YOUR FACE