Find the product of the zeroes of the cubic polynomial 3 2 4x + 8x - 6x - 2
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Answer: It will help u...
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The given polynomial is as follows :-
4 {x}^{2} - 8x
\rule{200}{2}
To find :- zeroes of the polynomial.
\rule{200}{2}
We can say that :-
4 {x}^{2} - 8x \\ \\ \\ = 4x(x - 2)
\rule{200}{2}
To get the zeroes, we need to equate the polynomial with zero.
Hence, equating the polynomial with its zeroes :-
\rule{200}{2}
4x(x - 2) = 0
Now, here,
Either 4x will be zero or (x-2) will be zero.
Therefore :-
4x = 0 \\ \\ x = 0
Or,
x - 2 = 0 \\ \\ x = 2
\rule{200}{2}
Thus,
Zeroes of the polynomial are 0 and 2
\rule{200}{2}
Hence, solved!
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Comments (5) Report
smile4045
tq
skh2
welcome^_^
smile4045
hmm
Noah11
Brilliant Answer Bhai!
skh2
Thanks a lot!!
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dikshaverma4you
dikshaverma4you
Answer:
The zeros of the polynomial are 0 and 2
Step-by-step explanation:
There is a short method as well to solve the question but I have solved the question with the most common method which is a bit long but understood.
Compare the given equation with the general equation, i.e., ax² + bx + c.
After comparing we get:-
a = 4 ; b = - 8 ; c = 0
By substituting these values in the discriminant formula we will find out the zeros of the polynomial.
I have attached the complete solution. Have a look over it.
Step-by-step explanation:
