Find the product of three consecutive odd
integers, if one of them is (2m+1).
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Answer:
Step-by-step explanation: hmugcmhfcmh=MHz
Answered by
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Step-by-step explanation:
(2m+1) (2m+3) (2m+5)
4m^2 + 6m + 2m +3 (2m+5)
4m^2 + 8m +3 (2m+5)
4m^3 + 20m^2 + 16m^2 + 40m + 6m + 15
4m^3 + 36m^2 + 46m + 15
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