Question

find the product of (x-1/x),(x+1/x),(x^2+1/x^2),(x^2+1/x^2)and (x^4-1/x^4)

Answer 1

Answer :

Now,

(x - 1/x) (x + 1/x) (x² + 1/x²) (x² + 1/x²) (x^4 - 1/x^4)

= (x² - 1/x²) (x² + 1/x²) (x² + 1/x²) (x^4 - 1/x^4)

= (x^4 - 1/x^4) (x² + 1/x²) (x^4 - 1/x^4)

= (x² + 1/x²) (x^4 - 1/x^4)²

= (x² + 1/x²) (x^8 + 1/x^8 - 2)

= x^10 + 1/x^6 - 2x² + x^6 + 1/x^10 - 2/x²,

which is the required product of the given terms.

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Answer 2

Answer:

It's 2 for both

Step-by-step explanation:

1) x^2 + 1/ x^2 = { x + 1/ x} ^2 - 2

= (2)^2 - 2

= 4 - 2 = 2

2) x^4 + 1/x^4 = { x^2 + 1/x^2}^2 - 2

= (2)^2 - 2

= 4-2 = 2

thanky u