Question

Find the product of (x + 1) (x3 + 2x2 + 3x – 8)

Answer 1

Required Answer:-

Question:

• Find the product of (x + 1) and (x³ + 2x² + 3x - 8)

Solution:

Given,

= (x + 1)(x³ + 2x² + 3x - 8)

= x(x³ + 2x² + 3x - 8) + 1(x³ + 2x² + 3x - 8)

= x⁴ + 2x³ + 3x² - 8x + x³ + 2x² + 3x - 8

Collect like terms,

= x⁴ + 2x³ + x³ + 3x² + 2x² - 8x + 3x - 8

= x⁴ + 3x³ + 5x² - 5x - 8

Therefore,

→ Product of (x + 1) and (x³ + 2x² + 3x - 8) = x⁴ + 3x³ + 5x² - 5x - 8

Answer:

• (x + 1)(x³ + 2x² + 3x - 8) = x⁴ + 3x³ + 5x² - 5x - 8