Question

Find the product of (x - 1x) (x + 1x) (x2 + 1x2)​

Answer 1

Answer:

$(x - 1x)(x + 1x)( {x}^{2} + {1x}^{2} )$

since

${a}^{2} - {b}^{2} = ( a+ b)(a -b )$

so

$(x - 1x)(x + 1x) = ( {x}^{2} - {1x}^{2} )$

so

$( {x}^{2} - {1x}^{2} )( {x}^{2} + {1x}^{2} ) \\ {x}^{2} - {1x}^{2}$

Answer 2

Answer:

$x ^{2} - y {}^{2} = (x + y)(x - y) \\ (x - 1x)(x + 1x) = x ^{2} - 1x ^{2} \\( x ^{2} - 1x ^{2})(x ^{2} + 1x^{2} ) \\ (x ^{2} ) {}^{2} - (1x {}^{2} ) {}^{2} \\ x {}^{4} - 1x {}^{4}$

is the answer

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