Question

Find the product of x^3, 1/2x^2 and -100x

Answer 1

Answer :-

Given,

${x}^{3}$
$\frac{1}{2 {x}^{2} }$
$- 100x$

To find,

Product of the given three numbers.

Main solution :-
${x}^{3} . \frac{1}{2 {x}^{2} } . - 100x$
${x}^{3} \times \frac{1}{2 {x}^{2} } \times ( - 100)x$
$\frac{ {x}^{3} \times 1 \times ( - 100)x}{2 {x}^{2} }$
$\frac{ {x}^{3} \times (- 1) \times 100 \times x }{2 {x}^{2} }$
$\frac{ {x}^{3 + 1} \times ( - 1) \times 100 }{2 {x}^{2} }$
$\frac{ {x}^{4} \times ( - 1) \times 100 }{2 {x}^{2} }$
$\frac{ {x}^{4} }{ {x}^{2} } \times \frac{( - 1) \times 100}{2}$
${x}^{4 - 2} \times ( - 1) \times 50$
${x}^{2} \times ( - 50)$
$- 50 {x}^{2} {answer}$

Answer 2

Step-by-step explanation:

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