Question

find the product of (x+y) (x- y) ( x2+ y2)

Answer 1

$(x + y)(x - y)( {x}^{2} + {y}^{2} )$
As we know that

(x+y) (x- y) = ( x2- y2)

$( {x}^{2} - {y}^{2} )( {x}^{2} + {y}^{2} )$

Taking x² as (a)
and y² as (b)

$(a - b)(a + b) \\ = {a}^{2} - {b}^{2}$
then

$( {x}^{2} )^{2} - ( {y}^{2} )^{2} \\ ({x}^{m}) ^{n} = {x}^{m \times n} \\ = {x}^{4} - {y}^{4}$

The product of (x+y) (x- y) ( x2+ y2) is x⁴ – y⁴

Answer 2

(x+y)(x−y)(x2+y2) 
As we know that 

(x+y) (x- y) = ( x2- y2)

( {x}^{2} - {y}^{2} )( {x}^{2} + {y}^{2} )(x2−y2)(x2+y2) 

Taking x² as (a)
and y² as (b)

\begin{lgathered}(a - b)(a + b) \\ = {a}^{2} - {b}^{2}\end{lgathered}(a−b)(a+b)=a2−b2​ 
then 

\begin{lgathered}( {x}^{2} )^{2} - ( {y}^{2} )^{2} \\ ({x}^{m}) ^{n} = {x}^{m \times n} \\ = {x}^{4} - {y}^{4}\end{lgathered}(x2)2−(y2)2(xm)n=xm×n=x4−y4​ 

The product of (x+y) (x- y) ( x2+ y2) is x⁴ – y⁴