Question

Find the product of x+y+z-√x√y-√y√z-√z√x and √x+√y+√z
Please answer this question in a paper
who will answer first and correct will be marked as brainliest

Answer 1

Solution:

Given x,y,z are in AP.

y-x = z-y

x-y = y-z

Taking reciprocal

1/(x-y) = 1/(y-z)

Rearranging we get

1/(√x-√y)(√x+√y) = 1/(√y-√z)(√y+√z)

(√y-√z)/(√x+√y) = (√x-√y)/(√y+√z)

Add √x and subtract √z on LHS and RHS respectively

[(√x+√y)-(√z+√x)]/(√x+√y) = [(√z+√x)-(√y+√z)]/(√y+√z)

Divide both isdes by (√z+√x)

[(√x+√y)-(√z+√x)]/(√x+√y)(√z+√x) = [(√z+√x)-(√y+√z)]/(√y+√z)(√z+√x)

1/(√z+√x) – 1/(√x+√y) = 1/(√y+√z) – 1/(√z+√x)

So 1/(√x+√y), 1/(√z+√x), 1/(√y+√z)

Answer 2

Answer:

The answer for the sum is (√y+X)