Question

find the product of
(x2+3xy) (4x)

2. 9pqr (2p2 q- 3p2 r)
3. 3\4a2[2\3b2+8ab]

Answer 1

Hey,

1.)(x²+3xy)(4x)=4x³+12x²y

2.)9pqr(2p²q-3p²r)=18p³q²r-27p³qr²

3.)3/4a²(2/3b²+8ab)=6/12a²b²+24ab/4a³b
=1/2a²b²+6/a².

HOPE IT HELPS YOU:-))

Answer 2

Ahoy!

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$->({x}^{2} + 3xy)(4x) \\ \\ 4{x}^{3} + 12{x}^{2}y \\ \\ ->9pqr({2p}^{2} - 3{p}^{2}r \\ \\ 18{p}^{3}qr - 27{p}^{3}q{r}^{2} \\ \\ ->3÷ 4{a}^{2} (2÷3{b}^{2} )+ 8ab) \\ \\ 3 ÷ 4{a}^{2} (2 + 24a{b}^{3}) ÷ 3{b}^{2} \\ \\ (6 + 72a{b}^{3}) ÷ 12{a}^{2}{b}^{2}$

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