find the product of (x2-4y2)and (x+y)find its value when x=1and y=2
Answers
Answered by
0
Answer:
-45
Step-by-step explanation:
Given (x^2-4y^2)(x+y) and x=1, y=2,
substitute the values into the equation.
= (1^2-4(2)^2)(1+2)
= (1-4(4))(3)
= (1-16)(3)
= (-15)(3)
= (-45)
Answered by
0
Answer:
Product of (x2-4y2)(x+y)
=x3+x2y-4xy2-4y3
It's value when x=1and y=2
=1+2-16-32
=3-48
=-45
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