Question

find the product of; (y-8) (3y+4)​

Answer 1

Answer:

$(y - 8)(3y + 4) \\ y(3y + 4) - 8(3y + 4) \\ = 3 {y}^{2} + 4y - 24y - 32 \\ = 3 {y}^{2} - 20y - 32$

I hope it will help you

Answer 2

Answer:

(y-8)(3y+4)

[y(3y+4)]+[-8(3y+4)]

(3y^2+4y)+(-24y-32)

3y^2+4y-24y-32

3y^2-20y-32