find the product of (z-1) (z-2)
Answers
Answered by
3
Answer:there are two ways of doing this
method 1
z
1
=
r
1
(
cos
θ
+
i
sin
θ
)
z
2
=
r
2
(
cos
ϕ
+
i
sin
ϕ
)
⇒
z
1
z
2
=
r
1
r
2
(
cos
(
θ
+
ϕ
)
+
i
sin
(
θ
+
ϕ
)
)
−
−
(
1
)
we have
z
1
=
4
(
cos
40
+
i
sin
40
)
z
2
=
2
(
cos
20
+
i
sin
20
)
∴
z
1
z
2
=
(
4
×
2
)
(
cos
(
40
+
20
)
+
i
sin
(
40
+
20
)
)
z
1
z
2
=
8
(
cos
60
+
i
sin
60
)
z
1
z
2
=
8
(
1
2
+
i
√
3
2
)
z
1
z
2
=
4
+
4
√
3
i
Step-by-step explanation:
Answered by
1
Answer:
z^2-z+2
Step-by-step explanation:
z^2-2z-z+2
z^2-z+2
Similar questions