Question

Find the product of zeroes of-2x^2+kx+6

Answer 1

Answer:

Step-by-step explanation:

product of zeroes=c/a

=6/2

=3

Answer 2

Answer:

$\boxed{\boxed{-3}}$

Step-by-step explanation:

- 2 x² + k x + 6 = 0

This is a standard quadratic equation of degree 2 .

Multiplying both sides by - 1 we get the following :

⇒ 2 x² - k x - 6 = 0

This can be compared with the standard form of quadratic equation given by :

ax² + bx + c = 0

From that we get the following :

a = 2

b = - k

c = - 6

Now having got these values ,

Product of zeroes = $\frac{c}{a}$

$\implies Product\:of\:zeroes\:=\frac{-6}{2}\\\\\implies -3$

Hence the product of zeroes will be - 3.

NOTE :

The sum of roots is given by $\frac{-b}{a}$

Since - b = k , in the equation the sum of roots depend on the value of 'k' which is not given to us .