Question

find the product of zeroes of quadratic polynomial 3(x^2)+5x-21​

Answer 1

Answer:

The zeros of the polynomial $3x^{2} +5x-21=0$ is

$x=\frac{-5+\sqrt{277} }{6}$  or   $x=\frac{-5-\sqrt{277} }{6}$

Step-by-step explanation:

We have the quadratic formula

$x=\frac{-b}{2a}$±$\frac{\sqrt{b^{2}-4ac } }{2a}$.

Here the values of     $a=3, b=5, c=-21$

substituting in the formula

$x=\frac{-5}{2(3)}$±$\frac{\sqrt{5^{2}-4(3)(21) } }{2(3)}$

  $=\frac{-5}{6}$±$\frac{\sqrt{25+252} }{6}$

  $=\frac{-5+\sqrt{277} }{6}$   or   $\frac{-5-\sqrt{277} }{6}$

hence the answer

thank you