Question

FIND THE product of zeroes of the quadratic polynomial P(Y)=3Y^2
- 7Y+6

Answer 1

Step-by-step explanation:

$p(y) = {3y}^{2} - 7y + 6 \\ \: \: \: \: \: a=3 \: \: \: \: b = - 7 \: \: \: c = 6 \\ product \: \: of \ \: zeroes= \frac{c}{a} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{6}{3} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: =2$

I hope this may help you

Have a great day