Question

Find the product of zeroes of x^3 + 4x^2+x-6​

Answer 1

hey mate!!

let us assume that the zeroes of the equation as

$\alpha$

$\beta$

$\gamma$

we know that

$\alpha \beta \gamma = - d \div a$

=-(-6)/1

=6

hope the answer helps u

Answer 2

Answer:

x^3+4x^2+x-6=(x-1)(x+2)(x+3)

zeros are 1,-2,-3

their product =6