Question

find the product of zeros of the quadratic polynomial 3x square + 5 x minus 2​

Answer 1

Here given polynomial :

p(x) = 3x²+5x-2

To Find: The product of it's zeroes.

Finding out zeroes :

Consider p(x) = 0

3x²+5x-2 = 0

3x²+6x-x-2 = 0

3x(x+2)-1(x+2) = 0

(x+2)(3x-1) = 0

Here x = ⅓ = α and x = -2 = β

Finding the sum of the zeroes :

αβ = ⅓ × -2 =

$\frac{ - 2}{3}$

OR

We can directly find out the product of it's zeroes by using the relationship between the zeroes and the coefficients and constant of the polynomial :

$\alpha \beta = \frac{constant}{coefficient \: of \: {x}^{2} } \\ \\ = \frac{ - 2}{3}$

Answer 2

Answer:  -2/3

Step-by-step explanation:

the product =c/a

so c=  -2

a=3

product=  -2/3

or do middle term spliting

3x^2+5x-2

3x^2+6x-x-2

3x(x+2)-1(x+2)

(x+2)(3x-1)

x=-2  x=1/3

-2  X   1/3==-2/3

it was too big to type but i did it plz mark it as the braniest one

thank you