find the product of zeros of xcube + 4x square + x -6
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Answered by
316
x³+4x²+x-6
a = 1, b = 4, c = 1, d = -6
→ Sum of zeroes = -b/a = -4
→ Sum of the product of zeroes taken two at a time = c/a = 1
→ Product of zeroes = -d/a = -(-6)/1 = 6
Hope it helps
a = 1, b = 4, c = 1, d = -6
→ Sum of zeroes = -b/a = -4
→ Sum of the product of zeroes taken two at a time = c/a = 1
→ Product of zeroes = -d/a = -(-6)/1 = 6
Hope it helps
Answered by
32
Hope it helps uuu..................
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