Question

find the product: (p+3) (p square - 3p+q)​

Answer 1

$(p + 3)( {p}^{2} - 3p + 9) \\ \\ p( {p}^{2} - 3p + 9) + 3( {p}^{2} - 3p + 9) \\ \\ {p}^{3} - 3 {p}^{2} + 9p + 3 {p}^{2} - 9 {p}^{2} + 27 \\ \\ {p}^{3} - 9 {p}^{2} + 9p + 27$

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Answer 2

Answer:

(p + 3) (p^2 -3p -q)

Step-by-step explanation

in distubutive method

=p x p^2 + 3 x p^2 - p x 3p + 3 x 3p - p x q + 3 x q

=p^3 + 3p^2 - 3p^2 + 9p - pq + 3q

=p^3 + 12q - pq

the answer is

p^3 + 12q - pq