find the product s(s^2-st) and find its value for s=2 and t=3 ?
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Answered by
21
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anuyadavtkgpdv4kr:
ASHOK L.H.S =R.H.S YOU DIDN'T DO
The question was to find the value....not to prove it
Ok but my sir said we have to prove it
okk
btw...its not ashok
what i did't understand it
your name is Ashk
aishwarya k.....its just a short form
Answered by
11
→s³-s²t or →s²(s-t) [R.H.S. Part]
When S=2 and t=3
s(s²-st)=2[2²-(2×3)]. [in L.H.S]
=2[4-6]
=2×-2
=(-4)
Here s²=s×s
and st=s×t
So the equation Becomes.
s[(s×s)-(s×t)]
=s³-s²t [in R.H.S]
=2³-2²×3
=8-4×3
=8-12
=(-4)
and Hence RHS = LHS.
and the Final Value is -4
When S=2 and t=3
s(s²-st)=2[2²-(2×3)]. [in L.H.S]
=2[4-6]
=2×-2
=(-4)
Here s²=s×s
and st=s×t
So the equation Becomes.
s[(s×s)-(s×t)]
=s³-s²t [in R.H.S]
=2³-2²×3
=8-4×3
=8-12
=(-4)
and Hence RHS = LHS.
and the Final Value is -4
prove it bro!
Its already Proved. Done...
no bro L.H.S =R.H.S
Okay i Will Mark the LHS and RHS
ok thanks Bro bye
Done. Could you mark it as Brainliest. Just Click the Crown Symbol in top of MY answer.
sorry bro i do on another person answer i am sending another question
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