Question

find the product (t²-2)(t²-5)​

Answer 1

Answer:

t^4-2t^2-5t^2+10=0

t^4-7t^2+10=0

t^4-7t^2=-10

t^2(t^2-7)=-10

t^2=-10 t^2-7=-10

t=√10i t^2=-3

t=√3i

Answer 2

Step-by-step explanation:

$( {t}^{2} - 2)( {t }^{2} - 5) \\ {t}^{2 + 2} - 5{t}^{2} - 2 {t}^{2} + 10 \\ {t}^{4} - 7 {t}^{2} + 10$