Question

find the product using identities of (-10/3pq³) ( 6/5p³q) please give me full explanation ​

Answer 1

Answer:

−4p  

4

q  

4

Step-by-step explanation:

(−  

3

10

​  

pq  

3

)×(  

5

6

​  

p  

3

q)

=(−  

3

10

​  

)×(  

5

6

​  

)(p  

3

q)×(pq  

3

)  

=−4p  

4

q  

4

Answer 2

Step-by-step explanation:

If the measures of the angles of a triangle are 2xdegree (3x-5) (4x-13 degree) then the value of X degree is

Given, ABC is a triangle

In which,

∠A=2x°

∠B=(3x-5)°

∠C=(4x-13)°

we need to find the value of x

we know that, sum of all angle in a triangle is 180°

2x+(3x-5)+(4x-13)=180°( ∠ sum property)

2x+3x-5+4x-13=180°

9x-18=180°

9x=180+18

9x=198

x=198/9

x=22°

VERIFICATION

(2×22)+(3×22-5)+(4×22-13)=180

44+61+75=180

180°=180°

LHS=RHS

HENCE,

∠A=2×22=44°

∠B=3×33-5=61°

∠C=4×22-13=75°

Therefore, the value of all angle in the triangle are 44°,61°and 75°.