Question

Find the product using identity: (4xy+1) exponent of 2

Answer 1

Answer:

16(xy)^2 + 8xy + 1

Step-by-step explanation:

(4xy + 1)^2

=(4xy)^2 + 2×(4xy)×1 + (1)^2

=16(xy)^2 + 8xy + 1

Answer 2

Thus, the product of $(4xy+1)^2$ is $16x^2y^2+8xy+1$.

Step-by-step explanation:

We have,

$(4xy+1)^2$

To find, the product of $(4xy+1)^2$ by using suitable identity = ?

∴ $(4xy+1)^2$

Here, a = 4xy and b = 1

We know that,

The algebraic identity,

$(a + b)^2=a^{2}+2ab+b^{2}$

∴ $(4xy+1)^2$

$=(4xy)^2+2(4xy)1+(1)^2$

$=4^2x^2y^2+(8xy)1+1$

= $16x^2y^2+8xy+1$

∴  The product of $(4xy+1)^2$ by using suitable identity $=16x^2y^2+8xy+1$

Thus, the product of $(4xy+1)^2$ is $16x^2y^2+8xy+1$.