Question

find the product using indentite (1/x+1/y) (1/x-1/y)
here indentite is (a+b) (a-b)
a square-b square​

Answer 1

Answer:

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Step-by-step explanation:

(1/x+1/y) (1/x-1/y)

here we can take the identity as(a+b)(a-b)=a²-b²

so,a=1/x and b=1/y

(1/x+1/y) (1/x-1/y)=1/x²-1/y²

=1/-x²-1/-y²

here the final answer is 1/-x²-1/-y² because the numerator is 1 and 1²= 1 and x²= -x² same way y²= -y²